35+18w-5w^2=0

Solution for 35+18w-5w^2=0 equation:

35+18w-5w^2=0

a = -5; b = 18; c = +35;
Δ = b2-4ac
Δ = 182-4·(-5)·35
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-32}{2*-5}=\frac{-50}{-10}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+32}{2*-5}=\frac{14}{-10}
=-1+2/5
$